Question:
The velocity of light in a medium of relative permittivity 2 and relative permeability 4.5 is (velocity of light in free space is c)
The velocity of light in a medium of relative permittivity 2 and relative permeability 4.5 is (velocity of light in free space is c)
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Refractive index \(n = \sqrt{\varepsilon_r \mu_r}\).
Updated On: Apr 24, 2026
- \(c\)
- \(\frac{c}{2}\)
- \(\frac{c}{3}\)
- \(\frac{c}{4}\)
- \(\frac{c}{\sqrt{3}}\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Velocity of light in a medium: \(v = \frac{c}{\sqrt{\varepsilon_r \mu_r}}\).
Step 2: Detailed Explanation:
\(v = \frac{c}{\sqrt{2 \times 4.5}} = \frac{c}{\sqrt{9}} = \frac{c}{3}\)
Step 3: Final Answer:
\(v = \frac{c}{3}\).
Velocity of light in a medium: \(v = \frac{c}{\sqrt{\varepsilon_r \mu_r}}\).
Step 2: Detailed Explanation:
\(v = \frac{c}{\sqrt{2 \times 4.5}} = \frac{c}{\sqrt{9}} = \frac{c}{3}\)
Step 3: Final Answer:
\(v = \frac{c}{3}\).
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