Question:

The values of the currents $I_1$, $I_2$, and $I_3$ flowing through the circuit given below is

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Always assign current directions first. Negative results indicate actual direction is opposite to assumed.
Updated On: May 1, 2026
  • $I_1 = -3$ A, $I_2 = 2$ A, $I_3 = -1$ A
  • $I_1 = 2$ A, $I_2 = -3$ A, $I_3 = -1$ A
  • $I_1 = 3$ A, $I_2 = -1$ A, $I_3 = -2$ A
  • $I_1 = 1$ A, $I_2 = -3$ A, $I_3 = -2$ A
  • $I_1 = 2$ A, $I_2 = -1$ A, $I_3 = -3$ A
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Solution and Explanation


Concept:
Use Kirchhoff’s laws:
• KCL: Sum of currents at a junction is zero
• KVL: Sum of voltages in a loop is zero

Step 1:
Apply KCL at node.
\[ I_2 = I_1 + I_3 \]

Step 2:
Apply KVL in upper loop.
\[ 14 - 4I_2 - 10 - 6I_1 = 0 \]

Step 3:
Apply KVL in lower loop.
\[ 10 - 6I_1 - 2I_3 = 0 \]

Step 4:
Solve equations.
From equations: \[ I_1 = 2,\quad I_2 = -1,\quad I_3 = -3 \]
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