Question:

The values of \(C_V\) and \(C_P\) for a diatomic gas are respectively \((R=\) gas constant\()\)

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Always remember: \[ C_P-C_V=R \] for an ideal gas.
Updated On: Apr 29, 2026
  • \(\dfrac{5}{2}R,\ \dfrac{7}{2}R\)
  • \(\dfrac{3}{2}R,\ \dfrac{5}{2}R\)
  • \(3R,\ 4R\)
  • \(\dfrac{5}{2}R,\ \dfrac{3}{2}R\)
  • \(\dfrac{7}{2}R,\ \dfrac{5}{2}R\)
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The Correct Option is A

Solution and Explanation

For a diatomic gas at ordinary temperatures: \[ C_V=\frac{5}{2}R \] and \[ C_P=C_V+R=\frac{5}{2}R+R=\frac{7}{2}R \] Hence, \[ \boxed{(A)\ \frac{5}{2}R,\ \frac{7}{2}R} \]
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