Question:

The values of \( a \), if \( f(x) = 2e^x - a e^{-x} + (2a+1)x - 3 \) increases for all \( x \), are in

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For expressions like \(e^x\) and \(e^{-x}\), substitute \(t=e^x\) and apply AM-GM.
Updated On: Apr 16, 2026
  • \([0,\infty)\)
  • \((-\infty,0]\)
  • \((-\infty,\infty)\)
  • \((1,\infty)\)
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The Correct Option is A

Solution and Explanation

Concept: Function increases for all \(x\) if: \[ f'(x) \ge 0 \quad \forall x \]

Step 1:
Differentiate.
\[ f'(x) = 2e^x + ae^{-x} + (2a+1) \]

Step 2:
Let \(t=e^x>0\).
\[ f'(x) = 2t + \frac{a}{t} + (2a+1) \]

Step 3:
Minimize expression.
Using AM-GM: \[ 2t + \frac{a}{t} \ge 2\sqrt{2a} \quad \text{(valid when } a \ge 0\text{)} \] \[ \Rightarrow f'(x) \ge 2\sqrt{2a} + (2a+1) \]

Step 4:
Ensure non-negative.
For \(a \ge 0\), RHS is always positive. \[ \Rightarrow f'(x) \ge 0 \quad \forall x \] Conclusion: \[ {a \in [0,\infty)} \]
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