Question:
The function $y = -x^{2 + 6x - 3}$ is increasing when:
The function $y = -x^{2 + 6x - 3}$ is increasing when:
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The vertex of this parabola is at $x = -b/2a = -6/(-2) = 3$. To the left of the vertex, the function rises.
Updated On: Apr 8, 2026
- $x<3$
- $x>3$
- $x<-3$
- $x>-3$
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The Correct Option is A
Solution and Explanation
Step 1: Concept
A function is increasing where its derivative $y'$ is positive.
Step 2: Analysis
$y' = -2x + 6$.
Set $-2x + 6>0 \Rightarrow 6>2x$.
Step 3: Conclusion
$x<3$.
Final Answer: (A)
A function is increasing where its derivative $y'$ is positive.
Step 2: Analysis
$y' = -2x + 6$.
Set $-2x + 6>0 \Rightarrow 6>2x$.
Step 3: Conclusion
$x<3$.
Final Answer: (A)
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