Question:
The value of R in the given circuit is:
The value of R in the given circuit is:
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Calculate the total resistance from V and I first to simplify the bridge equations.
Updated On: Apr 28, 2026
- $0.4\ \Omega$
- $8\ \Omega$
- $2\ \Omega$
- $0.8\ \Omega$
- $4\ \Omega$
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The Correct Option is
Solution and Explanation
Step 1: Concept
Use Ohm's Law $V = IR_{eq}$.
Step 2: Analysis
Total resistance $R_{eq} = \frac{V}{I} = \frac{4\ V}{0.25\ A} = 16\ \Omega$. The circuit has two parallel branches: $(2R+4R)$ and $(4R+6R)$.
Step 3: Calculation
$\frac{1}{R_{eq}} = \frac{1}{6R} + \frac{1}{10R} = \frac{5+3}{30R} = \frac{8}{30R} \implies 16 = \frac{30R}{8} \implies 128 = 30R \implies R \approx 4\ \Omega$. Final Answer: (E)
Use Ohm's Law $V = IR_{eq}$.
Step 2: Analysis
Total resistance $R_{eq} = \frac{V}{I} = \frac{4\ V}{0.25\ A} = 16\ \Omega$. The circuit has two parallel branches: $(2R+4R)$ and $(4R+6R)$.
Step 3: Calculation
$\frac{1}{R_{eq}} = \frac{1}{6R} + \frac{1}{10R} = \frac{5+3}{30R} = \frac{8}{30R} \implies 16 = \frac{30R}{8} \implies 128 = 30R \implies R \approx 4\ \Omega$. Final Answer: (E)
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