Question:
The equivalent capacitance of n capacitors of equal capacitance when connected in series and parallel are respectively $0.4\ \mu F$ and $10\ \mu F$. The capacitance of each capacitor is:
The equivalent capacitance of n capacitors of equal capacitance when connected in series and parallel are respectively $0.4\ \mu F$ and $10\ \mu F$. The capacitance of each capacitor is:
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The ratio $C_p/C_s = n^2$ is a useful identity for identical components.
Updated On: Apr 28, 2026
- $2\ \mu F$
- $4\ \mu F$
- $5\ \mu F$
- $6\ \mu F$
- $1\ \mu F$
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The Correct Option is A
Solution and Explanation
Step 1: Concept
For $n$ identical capacitors: $C_p = nC$ and $C_s = C/n$.
Step 2: Analysis
$nC = 10$ and $C/n = 0.4$.
Step 3: Calculation
Multiply the two equations: $(nC) \times (C/n) = 10 \times 0.4 \implies C^2 = 4 \implies C = 2\ \mu F$. Final Answer: (A)
For $n$ identical capacitors: $C_p = nC$ and $C_s = C/n$.
Step 2: Analysis
$nC = 10$ and $C/n = 0.4$.
Step 3: Calculation
Multiply the two equations: $(nC) \times (C/n) = 10 \times 0.4 \implies C^2 = 4 \implies C = 2\ \mu F$. Final Answer: (A)
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