Step 1: Understanding the Concept:
Since \(\text{cosec}^2\theta - 1 = \cot^2\theta\), we have \(\sqrt{\text{cosec}^2x^n - 1} = \cot x^n\) for the usual range where \(\cot x^n > 0\).
Step 2: Key Formula or Approach:
\(\frac{n}{x^{1-n}} = n x^{n-1}\), and \(\frac{d}{dx}(x^n) = nx^{n-1}\).
Step 3: Detailed Explanation:
The integral is \(\int nx^{n-1}\cot(x^n)\,dx\).
Put \(t = x^n\), so \(dt = nx^{n-1}dx\).
\[ \int \cot t\,dt = \log|\sin t| + c = \log(\sin x^n) + c \]
The answer is \(\log(\sin x^n)\), not \(\log(\sin x)\), because the substitution keeps the power inside the sine.
Final Answer:
The value is \(\log(\sin x^n) + c\), option (B).
\[ \boxed{\log(\sin x^n)+c} \]