Step 1: The escape velocity \( v_e \) is the minimum velocity required for an object to escape the gravitational pull of the planet.
The formula for escape velocity is: \[ v_e = \sqrt{\frac{2GM}{R}} \] where: - \( G \) is the gravitational constant,
- \( M \) is the mass of the planet,
- \( R \) is the radius of the planet.
Step 2: The escape velocity does not depend on the mass of the object being thrown, but depends on the mass \( M \) and radius \( R \) of the planet. Thus, the correct answer is that escape velocity depends on the mass, density, and radius of the planet.
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
In the travelling plane wave equation given by \( y = A \sin \omega \left( \frac{x}{v} - t \right) \), where \( \omega \) is the angular velocity and \( v \) is the linear velocity.
The dimension of \( \omega t \) is:
Kepler's second law (law of areas) of planetary motion leads to law of conservation of