Question:

The value of $\begin{vmatrix} a & a+b & a+2b \\ a+2b & a & a+b \\ a+b & a+2b & a \end{vmatrix}$ is equal to

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Adding all rows (or columns) is a powerful trick when each row has a common sum. Factor out the common element before expanding.
Updated On: Apr 8, 2026
  • $9a^{2}(a+b)$
  • $9b^{2}(a+b)$
  • $a^{2}(a+b)$
  • $b^{2}(a+b)$
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
Use row operations to simplify the determinant.
Step 2: Detailed Explanation:
Apply $R_1 \to R_1 + R_2 + R_3$. Each element of the new first row equals $3(a+b)$, so factor out $3(a+b)$. After further row and column operations the determinant evaluates to $9b^2(a+b)$.
Step 3: Final Answer:
The value of the determinant is $9b^2(a+b)$.
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