Question

The truth table for this given circuit is :The truth table for this given circuit is :

• A.

  A	B	Y
  0	0	1
  0	1	1
  1	0	1
  1	1	0

• B.

  A	B	Y
  0	0	0
  0	1	1
  1	0	0
  1	1	1

• C.

  A	B	Y
  0	0	0
  0	1	0
  1	0	0
  1	1	1

• D.

  A	B	Y
  0	0	1
  0	1	0
  1	0	1
  1	1	0

Answer 1

The Correct Option is B

To determine the truth table for the given circuit, we need to analyze the logic gates involved and the connections between the inputs and outputs. 

Here's how the circuit works:

• The circuit includes an OR gate and a NOT gate at the input A, as well as an AND gate.
• The input A is connected to a NOT gate, meaning the output of the NOT gate is \(NOT(A)\).
• This \(NOT(A)\) is then fed into an OR gate along with input B.
• The output of the OR gate is \(NOT(A) + B\).
• Finally, this result is fed into an AND gate along with input B to produce the output \(Y\).

Now, let’s evaluate the output Y for each combination of A and B:

A	B	Y
0	0	0
0	1	1
1	0	0
1	1	1

The correct truth table for the given circuit is the one matching these outputs, which corresponds to:

A	B	Y
0	0	0
0	1	1
1	0	0
1	1	1