Question:

The substrate for enzyme acyl CoA acetyl transferase is

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Remember the order of intermediates in the $\beta$-oxidation pathway:
Acyl-CoA $\rightarrow$ Trans-$\Delta^2$-enoyl-CoA $\rightarrow$ L-$\beta$-hydroxyacyl-CoA $\rightarrow$ $\beta$-ketoacyl-CoA $\rightarrow$ Shortened Acyl-CoA + Acetyl-CoA.
Thiolase always acts on the "keto" intermediate.
  • Acyl CoA
  • Trans $\Delta^2$ Enoyl CoA
  • L-$\beta$-hydroxy acyl CoA
  • $\beta$-keto acyl CoA
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The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Acyl-CoA acetyltransferase, commonly known as thiolase, is the enzyme that catalyzes the fourth and final step of the mitochondrial $\beta$-oxidation pathway.
This pathway sequentially breaks down fatty acids to generate acetyl-CoA molecules for the citric acid cycle.
Detailed Explanation:
The $\beta$-oxidation of fatty acids involves a repeating sequence of four enzymatic reactions:
1. Oxidation of acyl-CoA to trans-$\Delta^2$-enoyl-CoA, catalyzed by acyl-CoA dehydrogenase.
2. Hydration of trans-$\Delta^2$-enoyl-CoA to L-$\beta$-hydroxyacyl-CoA, catalyzed by enoyl-CoA hydratase.
3. Oxidation of L-$\beta$-hydroxyacyl-CoA to $\beta$-ketoacyl-CoA, catalyzed by $\beta$-hydroxyacyl-CoA dehydrogenase.
4. Thiolytic cleavage of $\beta$-ketoacyl-CoA by a molecule of free coenzyme A (CoASH), catalyzed by acyl-CoA acetyltransferase (thiolase).
In this final step, the thiolase cleaves the bond between the $\alpha$ and $\beta$ carbons of the $\beta$-ketoacyl-CoA substrate.
This reaction yields one molecule of acetyl-CoA and a shortened acyl-CoA chain (shortened by two carbons), which can re-enter the $\beta$-oxidation cycle.

Step 2: Final Answer:

The substrate for the enzyme acyl-CoA acetyltransferase is $\beta$-ketoacyl-CoA.
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