Question:
The standard molar enthalpy of vaporisation (\(\Delta_\text{vap} H^\circ\)) of A, B, and C liquids is 23.3, 41, and 29 kJ mol\(^{-1}\) respectively. The correct order of dipole-dipole attractive forces in these liquids is:
The standard molar enthalpy of vaporisation (\(\Delta_\text{vap} H^\circ\)) of A, B, and C liquids is 23.3, 41, and 29 kJ mol\(^{-1}\) respectively. The correct order of dipole-dipole attractive forces in these liquids is:
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Stronger dipole-dipole forces correspond to higher enthalpies of vaporisation in polar liquids.
Updated On: Jun 26, 2026
- B > C > A
- B > A > C
- A > C > B
- A > B > C
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The Correct Option is A
Solution and Explanation
Step 1: Understand relation between enthalpy of vaporization and dipole-dipole forces.
Higher enthalpy of vaporization indicates stronger intermolecular forces, including dipole-dipole attractions.
Step 2: Compare enthalpies.
\[ \Delta_\text{vap} H^\circ: B (41) \gt C (29) \gt A (23.3) \] Hence, the dipole-dipole interactions follow the same order.
Step 3: Conclusion.
\[ \boxed{B \gt C \gt A} \]
Higher enthalpy of vaporization indicates stronger intermolecular forces, including dipole-dipole attractions.
Step 2: Compare enthalpies.
\[ \Delta_\text{vap} H^\circ: B (41) \gt C (29) \gt A (23.3) \] Hence, the dipole-dipole interactions follow the same order.
Step 3: Conclusion.
\[ \boxed{B \gt C \gt A} \]
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