The standard emf of a cell Zn/Zn\(^{2+}\) || Fe\(^{2+}\)/Fe if electrode potentials for (Zn/Zn\(^{2+}\)) and (Fe\(^{2+}\)/Fe) are 0.763 V and -0.44 V respectively is
Show Hint
- +0.323 V
- -1.203 V
- +1.203 V
- -0.323 V
The Correct Option is A
Solution and Explanation
\(E_{cell} = E_{cathode} - E_{anode}\).
Step 2: Detailed Explanation:
Zn oxidizes (\(E_{ox} = 0.763\) V), Fe\(^{2+}\) reduces (\(E_{red} = -0.44\) V)
\(E_{cell} = 0.763 + (-0.44) = 0.323\ \mathrm{V}\)
Step 3: Final Answer:
EMF is +0.323 V.
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