Question:
The oxidation number of N and Cl in \( NOClO_4 \) respectively are
The oxidation number of N and Cl in \( NOClO_4 \) respectively are
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In oxyacids and their salts, the central atom often has high positive oxidation states. Perchlorate has Cl in +7 state.
Updated On: May 2, 2026
- +2 and +7
- +3 and +7
- -3 and +5
- +2 and -7
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept:
The compound is \(NOClO_4\), which is nitrosyl perchlorate. It can be written as \(NO^+\) and \(ClO_4^-\).
Step 2: Detailed Explanation:
In \(NO^+\), let oxidation number of N be \(x\). \(x + (-2) = +1 \Rightarrow x = +3\). In \(ClO_4^-\), let oxidation number of Cl be \(y\). \(y + 4(-2) = -1 \Rightarrow y - 8 = -1 \Rightarrow y = +7\).
Step 3: Final Answer:
Thus, oxidation numbers are N = +3 and Cl = +7, option (B).
The compound is \(NOClO_4\), which is nitrosyl perchlorate. It can be written as \(NO^+\) and \(ClO_4^-\).
Step 2: Detailed Explanation:
In \(NO^+\), let oxidation number of N be \(x\). \(x + (-2) = +1 \Rightarrow x = +3\). In \(ClO_4^-\), let oxidation number of Cl be \(y\). \(y + 4(-2) = -1 \Rightarrow y - 8 = -1 \Rightarrow y = +7\).
Step 3: Final Answer:
Thus, oxidation numbers are N = +3 and Cl = +7, option (B).
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