Question

The specific conductivity of 0.1 N KCl solution is 0.0129 ohm\(^{-1}\) cm\(^{-1}\). The resistance of the solution in the cell is 100 ohm. The cell constant of the cell will be

• A. 1.10
• B. 1.29
• C. 0.56
• D. 2.80

Hint:

Cell constant = l/A, units cm\(^{-1}\).

Answer 1

The Correct Option is B

Step 1: Understanding the Concept:
\(\kappa = (1/R) \times\) cell constant.
Step 2: Detailed Explanation:
Cell constant = \(\kappa \times R = 0.0129 \times 100 = 1.29\ \mathrm{cm}^{-1}\)
Step 3: Final Answer:
Cell constant is 1.29.