Question:
The simultaneous equations \( Kx + 2y = 1 \), \( K(1 - y) - 2x = 2 \) and \( K + 2y = 3 \) have only one solution when
The simultaneous equations \( Kx + 2y = 1 \), \( K(1 - y) - 2x = 2 \) and \( K + 2y = 3 \) have only one solution when
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For simultaneous equations, solve step-by-step to find the values of unknowns that satisfy all equations.
Updated On: Jan 6, 2026
- \( K = -2 \)
- \( K = 0 \)
- \( K = 1 \)
- \( K = 10 \)
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The Correct Option is C
Solution and Explanation
Step 1: Solving the system of equations.
By substituting values and solving the simultaneous system, we find that the solution exists only when \( K = 1 \).
Step 2: Conclusion.
Thus, the correct answer is option (C).
Final Answer: \[ \boxed{\text{(C) } K = 1} \]
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