Question:
The set with only ambidentate ligands in the following is
The set with only ambidentate ligands in the following is
Show Hint
Common ambidentate ligands are:
\[
NO_2^-,\ CN^-,\ SCN^-
\]
because they can bind through two different atoms.
Updated On: Jun 25, 2026
- \(NO_3^-,\ Br^-,\ C_2O_4^{2-}\)
- \(NO_2^-,\ CN^-,\ SCN^-\)
- \(NO_2^-,\ C_2O_4^{2-},\ NH_3\)
- \(SCN^-,\ CO,\ NH_3\)
Show Solution
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The Correct Option is B
Solution and Explanation
Step 1: Understand ambidentate ligands.
Ambidentate ligands are ligands that can coordinate through two different donor atoms, but only one donor atom at a time.
Step 2: Identify ambidentate ligands.
\[ NO_2^- \] can coordinate through: \[ N \quad \text{or} \quad O \] \[ CN^- \] can coordinate through: \[ C \quad \text{or} \quad N \] \[ SCN^- \] can coordinate through: \[ S \quad \text{or} \quad N \] Thus, all three are ambidentate ligands.
Step 3: Check remaining ligands.
\[ Br^- \] is monodentate only.
\[ C_2O_4^{2-} \] is bidentate, not ambidentate.
\[ NH_3 \] and \[ CO \] are monodentate ligands.
Hence, only option (2) contains exclusively ambidentate ligands.
Step 4: Final conclusion.
Therefore, the correct set is \[ \boxed{NO_2^-,\ CN^-,\ SCN^-} \]
Ambidentate ligands are ligands that can coordinate through two different donor atoms, but only one donor atom at a time.
Step 2: Identify ambidentate ligands.
\[ NO_2^- \] can coordinate through: \[ N \quad \text{or} \quad O \] \[ CN^- \] can coordinate through: \[ C \quad \text{or} \quad N \] \[ SCN^- \] can coordinate through: \[ S \quad \text{or} \quad N \] Thus, all three are ambidentate ligands.
Step 3: Check remaining ligands.
\[ Br^- \] is monodentate only.
\[ C_2O_4^{2-} \] is bidentate, not ambidentate.
\[ NH_3 \] and \[ CO \] are monodentate ligands.
Hence, only option (2) contains exclusively ambidentate ligands.
Step 4: Final conclusion.
Therefore, the correct set is \[ \boxed{NO_2^-,\ CN^-,\ SCN^-} \]
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