Question:
The salt which has van’t Hoff factor (\(i\)) as 1.82 in 0.001 m aqueous solution is}
The salt which has van’t Hoff factor (\(i\)) as 1.82 in 0.001 m aqueous solution is}
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If \(i\) is slightly less than the expected whole number, think about incomplete dissociation or ion pairing.
Updated On: Apr 24, 2026
- \(K_2SO_4\)
- \(MgSO_4\)
- \(KCl\)
- \(NaCl\)
- \(HCl\)
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The Correct Option is B
Solution and Explanation
The van’t Hoff factor tells the effective number of particles in solution.
Strong electrolytes like \(KCl\), \(NaCl\), and \(HCl\) dissociate almost completely into 2 ions, so \(i\) is close to 2.
\(K_2SO_4\) dissociates into 3 ions, so \(i\) is closer to 3.
But \(MgSO_4\) is known to show incomplete dissociation and ion pairing in solution, so its \(i\) can be less than 2, such as 1.82.
Hence, the correct answer is: \[ \boxed{(B)\ MgSO_4} \]
Hence, the correct answer is: \[ \boxed{(B)\ MgSO_4} \]
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