Step 1:
Given:
\[
R=300000+2250x-75x^{2}
\]
This is a quadratic function.
Step 2:
Revenue is maximum when:
\[
\frac{dR}{dx}=0
\]
Differentiate revenue function:
\[
\frac{dR}{dx}=2250-150x
\]
Step 3: x
Set derivative equal to zero:
\[
2250-150x=0
\]
\[
150x=2250
\]
\[
x=15
\]
Step 4:
Therefore, revenue is maximum at:
\[
\boxed{15 \text{ units}}
\]
Hence, the correct answer is:
\[
\boxed{\text{(2) 15 units}}
\]