Question:

The revenue function of a firm is given as \[ R=300000+2250x-75x^{2} \] Where $R$ is the revenue and $x$ is the quantity sold. The revenue maximizing level of quantity sold is:

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Logic Tip: For quadratic functions of the form $ax^2+bx+c$, maximum occurs at $x=-\frac{b}{2a}$ when $a<0$.
Updated On: May 29, 2026
  • 5.47 units
  • 15 units
  • 30 units
  • 45 units
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The Correct Option is B

Solution and Explanation

Step 1:
Given: \[ R=300000+2250x-75x^{2} \] This is a quadratic function.

Step 2:
Revenue is maximum when: \[ \frac{dR}{dx}=0 \] Differentiate revenue function: \[ \frac{dR}{dx}=2250-150x \]

Step 3: x
Set derivative equal to zero: \[ 2250-150x=0 \] \[ 150x=2250 \] \[ x=15 \]

Step 4:
Therefore, revenue is maximum at: \[ \boxed{15 \text{ units}} \] Hence, the correct answer is: \[ \boxed{\text{(2) 15 units}} \]
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