Question:

The relation between equilibrium constants \(K_C\) and \(K_P\) is:

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Remember: \(\Delta n = moles_{products} - moles_{reactants}\) for gases when converting between \(K_C\) and \(K_P\).
Updated On: Jun 19, 2026
  • \(K_P = K_C(RT)^{\Delta n}\)
  • \(K_P = K_C(RT)^{1/\Delta n}\)
  • \(K_C = K_P(RT)^{\Delta n}\)
  • \(K_C = K_P(RT)^{1/\Delta n}\)
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The Correct Option is A

Solution and Explanation

Step 1: Definition of \(K_C\) and \(K_P\).
\(K_C\) is equilibrium constant in terms of concentration (mol/L), \(K_P\) is in terms of partial pressures (atm).

Step 2: Use ideal gas relation.

For a gas, \(P = CRT\), where \(C\) is molar concentration.

Step 3: Express \(K_P\) in terms of \(K_C\).

\[ K_P = \prod (P_i)^{\nu_i} = \prod (C_i RT)^{\nu_i} = K_C (RT)^{\sum \nu_i} \]

Step 4: Define \(\Delta n\).

\(\Delta n = \sum \nu_{\text{products}} - \sum \nu_{\text{reactants}}\).

Step 5: Substitute \(\Delta n\).

\[ K_P = K_C (RT)^{\Delta n} \]

Step 6: Final conclusion.

This is the standard relation between \(K_P\) and \(K_C\) for gaseous equilibria.
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