Ozonolysis of but-2-ene in the presence of water and zinc dust breaks the double bond, forming two carbonyl compounds. The further reduction of ozonolysis products gives ethanol.
- Step 1: Ozone cleaves the double bond, forming two aldehydes or ketones.
- Step 2: Reduction with Zn/H\(_2\)O converts one of the fragments into ethanol.
Thus, the correct reagent for this conversion is O\(_3\)/H\(_2\)O-Zn dust.
The decreasing order of stability of the following carbocations is:
\( (i) \text{(CH}_3\text{)}_3\text{C}^+ \quad (ii) \text{(CH}_3\text{)}_2\text{C-CH}_2^+ \quad (iii) \text{CH}_3\text{CH}_2\text{-CH}_2^+ \)
If $ | \vec{a} | = 3 $, $ | \vec{b} | = 2 $, then find $ (3\vec{a} - 2\vec{b}) \cdot (3\vec{a} + 2\vec{b}) $.