According to Ohm's Law, Voltage (V) = Current (I) × Resistance (R)

According to Ohm's Law, Voltage (V) = Current (I) × Resistance (R)
From the Given equation, V = 3V, R = 200 ohm, I =?
Here, across the diode potential barrier ΔV=0.7 volts
The formula will look like, I=(V−ΔV)/R
Therefore, I= (3−0.7) /200
=0.0115 A
=11.5 mA
Discover More Topics from Chapter: Current Electricity
The Correct Answer is (C): 11.5 mA

The Correct Answer is (C): 11.5 mA
This problem can also be solved by using Kirchoff's Law,
Then the equation will look like, 3-V- I (200) = 0
Here, V = 0.7V
Therefore, 3 - 0.7 - 200I = 0
⇒200I = 2.3
⇒ I = 2.3/200 = 0.0115
So, I = 11.5 mA
According to Kirchhoff's Current Law, no charge is wasted and the total current flowing into a junction in an electric circuit equals the charge leaving the node.
According to Kirchhoff's Voltage Law, the voltage in a closed network is equal to the total of all voltage drops in the loop and is zero.
In order to simplify the circuits and calculate the quantum of current and voltage in circuits, Kirchhoff's laws or Kirchhoff's rules are used to analyze complicated electrical circuits.
Also Check Out:
Related Articles | ||
|---|---|---|
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :

A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]
Current electricity is defined as the flow of electrons from one section of the circuit to another.
There are two types of current electricity as follows:
The current electricity whose direction remains the same is known as direct current. Direct current is defined by the constant flow of electrons from a region of high electron density to a region of low electron density. DC is used in many household appliances and applications that involve a battery.
The current electricity that is bidirectional and keeps changing the direction of the charge flow is known as alternating current. The bi-directionality is caused by a sinusoidally varying current and voltage that reverses directions, creating a periodic back-and-forth motion for the current. The electrical outlets at our homes and industries are supplied with alternating current.