Question:

The reaction of diborane in diethyl ether with \(X\) gives metalloborohydride. \(X\) is a

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Diborane reacts with metal hydrides to form metal borohydrides: \[ MH+B_2H_6 \rightarrow MBH_4 \] Example: \[ NaH+B_2H_6 \rightarrow NaBH_4 \]
Updated On: Jun 24, 2026
  • Metal
  • Metal halide
  • Metal hydride
  • Metal oxide
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The Correct Option is C

Solution and Explanation

Step 1: Recall the reaction of diborane.
Diborane \[ B_2H_6 \] reacts with metal hydrides in diethyl ether to form metal borohydrides.
For example, \[ 2NaH+B_2H_6 \rightarrow 2NaBH_4 \] where \[ NaBH_4 \] is sodium borohydride.

Step 2: Identify the substance \(X\).
Since metalloborohydrides are produced by the reaction of diborane with metal hydrides, the substance \[ X \] must be a metal hydride.

Step 3: Analyze other options.

Metal: Metals do not directly form metalloborohydrides with diborane under these conditions.

Metal halide: Metal halides generally do not produce borohydrides directly with diborane.

Metal oxide: Metal oxides react differently and do not form metalloborohydrides.
Hence, only metal hydrides give the required product.

Step 4: Final conclusion.
Therefore, \[ \boxed{X=\text{Metal hydride}} \]
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