Question:

The ratio of the weights of an object of mass $m$ at a height $R$ and $2R$ from the surface of earth is ($R$ is the radius of earth)

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Weight varies inversely with square of distance from earth’s center: - Always use $(R + h)$ in formula, not just $h$
Updated On: Apr 30, 2026
  • $4:9$
  • $1:1$
  • $9:4$
  • $1:2$
  • $4:1$
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The Correct Option is C

Solution and Explanation

Concept: Weight at height $h$ from earth’s surface: \[ W = \frac{GMm}{(R+h)^2} \]

Step 1:
Find weight at height $R$.
\[ W_1 = \frac{GMm}{(R+R)^2} = \frac{GMm}{(2R)^2} = \frac{GMm}{4R^2} \]

Step 2:
Find weight at height $2R$.
\[ W_2 = \frac{GMm}{(R+2R)^2} = \frac{GMm}{(3R)^2} = \frac{GMm}{9R^2} \]

Step 3:
Find ratio.
\[ \frac{W_1}{W_2} = \frac{\frac{1}{4R^2}}{\frac{1}{9R^2}} = \frac{9}{4} \]
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