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the ratio of the wavelength of the last line of pa
Question:
The ratio of the wavelength of the last line of Paschen series to that of Balmer series is
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Last line â \(n_2 = \infty\)
MHT CET - 2025
MHT CET
Updated On:
Apr 26, 2026
\(\frac{9}{4}\)
\(\frac{3}{2}\)
\(\frac{2}{3}\)
\(\frac{4}{9}\)
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The Correct Option is
A
Solution and Explanation
Concept:
Last line corresponds to \(n_2 \to \infty\): \[ \frac{1}{\lambda} = R \left( \frac{1}{n_1^2} \right) \]
Step 1:
Paschen series. \[ n_1 = 3 \Rightarrow \frac{1}{\lambda_P} = \frac{R}{9} \] \[ \lambda_P = \frac{9}{R} \]
Step 2:
Balmer series. \[ n_1 = 2 \Rightarrow \frac{1}{\lambda_B} = \frac{R}{4} \] \[ \lambda_B = \frac{4}{R} \]
Step 3:
Ratio. \[ \frac{\lambda_P}{\lambda_B} = \frac{9/R}{4/R} = \frac{9}{4} \]
Step 4:
Conclusion. \[ \frac{\lambda_P}{\lambda_B} = \frac{9}{4} \]
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