Question:

The ratio of the magnitudes of gravitational potential energy to that of kinetic energy of an earth satellite of mass $m$ revolving in any orbit is

Show Hint

For satellites: potential energy is twice kinetic energy in magnitude.
Updated On: Apr 24, 2026
  • $1:2$
  • $2:1$
  • $2:3$
  • $1:3$
  • $3:1$
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Concept:
• Total energy of satellite: \[ U = -2K \]

Step 1:
Take magnitudes
\[ |U| = 2K \]

Step 2:
Ratio
\[ |U| : K = 2 : 1 \] Final Conclusion:
Option (B)
Was this answer helpful?
0
0