Question

The ratio of rate of diffusion of SO$_2$ to CH$_4$ is

• A. 1:1
• B. 1:2
• C. 2:1
• D. 4:1

Hint:

Remember: \( r \propto \frac{1}{\sqrt{M}} \)
Use molar masses in g/mol in Graham’s law.

Answer 1

The Correct Option is B

From Graham’s Law: \[ \frac{r_1}{r_2} = \sqrt{\frac{M_2}{M_1}} \quad \text{(Rate inversely proportional to molar mass)} \] Molar masses: SO$_2$ = 64, CH$_4$ = 16 \[ \Rightarrow \frac{r_{\text{CH}_4}}{r_{\text{SO}_2}} = \sqrt{\frac{64}{16}} = \sqrt{4} = 2 \Rightarrow \frac{r_{\text{SO}_2}}{r_{\text{CH}_4}} = \frac{1}{2} \]