Question:
The ratio of distances traversed by a freely falling body in successive intervals of time is
The ratio of distances traversed by a freely falling body in successive intervals of time is
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Distances in successive seconds follow odd number pattern.
Updated On: Apr 24, 2026
- $3:4:6:9$
- $1:3:6:9$
- $1:2:4:6$
- $2:5:7:9$
- $1:3:5:7$
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The Correct Option is
Solution and Explanation
Concept:
• Distance in $n^{th}$ second: \[ s_n = \frac{g}{2}(2n-1) \]
Step 1: Compute ratios
\[ s_1:s_2:s_3:s_4 = 1:3:5:7 \] Final Conclusion:
Option (E)
• Distance in $n^{th}$ second: \[ s_n = \frac{g}{2}(2n-1) \]
Step 1: Compute ratios
\[ s_1:s_2:s_3:s_4 = 1:3:5:7 \] Final Conclusion:
Option (E)
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