Question:
The rate constant of a reaction is
\[
1.5\,mol^{-3/2}L^{3/2}s^{-1}
\]
What is the order of this reaction?
The rate constant of a reaction is
\[
1.5\,mol^{-3/2}L^{3/2}s^{-1}
\]
What is the order of this reaction?
Show Hint
The unit of rate constant directly reveals the order of reaction.
Updated On: Jun 18, 2026
- 1.0
- 3.0
- 1.5
- 2.5
Show Solution
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The Correct Option is D
Solution and Explanation
Concept:
For an \(n^{th}\) order reaction,
\[
[k]=(mol\,L^{-1})^{1-n}s^{-1}
\]
Step 1: Compare powers of concentration.
Given, \[ k=mol^{-3/2}L^{3/2}s^{-1} \] Thus \[ 1-n=-\frac{3}{2} \]
Step 2: Calculate reaction order.
\[ n=1+\frac{3}{2} \] \[ n=\frac{5}{2} \] \[ \boxed{n=2.5} \]
Step 1: Compare powers of concentration.
Given, \[ k=mol^{-3/2}L^{3/2}s^{-1} \] Thus \[ 1-n=-\frac{3}{2} \]
Step 2: Calculate reaction order.
\[ n=1+\frac{3}{2} \] \[ n=\frac{5}{2} \] \[ \boxed{n=2.5} \]
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