In Haber’s process of manufacture of ammonia, the ‘catalyst’, the ‘promoter’, and‘ poison for the catalyst’ are respectively:
\( Fe, Mo, CO \)
Step 1: Understanding the Haber Process
The Haber process is used for the industrial production of ammonia (\( NH_3 \)) from nitrogen (\( N_2 \)) and hydrogen (\( H_2 \)) under high pressure and temperature. The reaction is: \[ N_2 + 3H_2 \rightleftharpoons 2NH_3 \]
Step 2: Identifying the Catalyst, Promoter, and Poison
- Catalyst: Iron (\( Fe \)) is used as the main catalyst to increase the rate of reaction.
- Promoter: Molybdenum (\( Mo \)) is added as a promoter to enhance the efficiency of iron as a catalyst.
- Poison for the Catalyst: Carbon monoxide (\( CO \)) acts as a poison for the iron catalyst by adsorbing on its active sites and deactivating it.
Step 3: Evaluating the Given Options
- Option (1): Incorrect, as tungsten (\( W \)) is not used in the Haber process.
- Option (2): Incorrect, as cobalt (\( Co \)) is not the main catalyst.
- Option (3): Incorrect, as \( CO_2 \) is not the primary catalyst poison.
- Option (4): Correct, as the correct catalyst is \( Fe \), the promoter is \( Mo \), and the poison is \( CO \).
Thus, the correct answer is
Option (4).
| Molisch's lest | Barfoed Test | Biuret Test | |
|---|---|---|---|
| A | Positive | Negative | Negativde |
| B | Positive | Positive | Negative |
| C | Negative | Negative | Positive |
The rate law for the decomposition of hydrogen iodide is - = d[HI]/dt = k[HI]2. The units of rate constant k are:
For a first-order reaction, the graph between \( \log \frac{a}{(a - x)} \) (on y-axis) and time (in min, on x-axis) gave a straight line passing through the origin. The slope is \( 2 \times 10^{-3} \) min\(^{-1}\). What is the rate constant (in min\(^{-1}\))?
Among the following, the calcination process is:
