Question:

The radius of the circle \( x^{2} + y^{2} - 4x + 6y - 12 = 0 \) is:

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The center of this circle is $(-g, -f)$, which is $(2, -3)$.
Updated On: Apr 8, 2026
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The Correct Option is A

Solution and Explanation

Step 1: Concept
For the circle $x^2 + y^2 + 2gx + 2fy + c = 0$, radius $r = \sqrt{g^2 + f^2 - c}$.
Step 2: Analysis

$2g = -4 \Rightarrow g = -2$; $2f = 6 \Rightarrow f = 3$; $c = -12$.
$r = \sqrt{(-2)^2 + (3)^2 - (-12)} = \sqrt{4 + 9 + 12}$.
Step 3: Conclusion

$r = \sqrt{25} = 5$.
Final Answer: (A)
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