Question:

The area (in square unit) of the circle which touches the lines $4x+3y=15$ and $4x+3y=5$ is

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For two parallel lines $ax+by+c_1=0$ and $ax+by+c_2=0$, the distance between them is $\frac{|c_1 - c_2|}{\sqrt{a^2 + b^2}}$.
Updated On: Apr 10, 2026
  • $4\pi$
  • $3\pi$
  • $2\pi$
  • $\pi$
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The Correct Option is D

Solution and Explanation

Step 1: Distance Between Lines
The two lines are parallel. The distance between them is the diameter of the circle.
$d = \frac{|c_1 - c_2|}{\sqrt{a^2 + b^2}} = \frac{|15 - 5|}{\sqrt{4^2 + 3^2}} = \frac{10}{5} = 2$.
Step 2: Determine Radius

Diameter $d = 2$, so radius $r = \frac{2}{2} = 1$.
Step 3: Calculate Area

Area $= \pi r^2 = \pi(1)^2 = \pi$ square unit.
Final Answer: (d)
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