Question:

The Radial wave function for 2p orbital is:

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2p has 0 radial nodes, so look for the simplest version with a '$\sigma$' term but no subtraction factor like $(1-\sigma)$.
Updated On: May 15, 2026
  • $2(\frac{z}{a_{0}})^{\frac{3}{2}}e^{-\sigma}$
  • $2^{-\frac{3}{2}}(\frac{z}{a_{0}})^{\frac{3}{2}}(e^{-\sigma})e^{-\frac{\sigma}{2}}$
  • $2^{-1}(\frac{z}{a_{0}})^{\frac{3}{2}}\sigma e^{-\frac{\sigma}{2}}$
  • $2^{-1}(\frac{z}{a_{0}})^{\frac{3}{2}}(1-\sigma)e^{-\frac{\sigma}{2}}$
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The Correct Option is C

Solution and Explanation


Step 1: Concept
Radial wave functions ($R_{n,l}$) describe the probability of finding an electron at a distance $r$ from the nucleus.

Step 2: Meaning
The form of the function depends on the principal quantum number ($n$) and azimuthal quantum number ($l$).

Step 3: Analysis
For a 2p orbital ($n=2, l=1$), the radial part contains a term proportional to $\sigma$ (where $\sigma$ is related to $r$) and an exponential decay term $e^{-\sigma/2}$. It does not have any radial nodes (since $n-l-1 = 0$), so there is no $(1-\sigma)$ factor.

Step 4: Conclusion
Option (C) correctly identifies the mathematical form for the 2p radial wave function. Final Answer: (C)
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