The process shown in the question involves heating a solid to convert it into vapour, followed by cooling the vapour back into a solid.
This is a typical example of sublimation, where a substance transitions directly from a solid to a gas and then back to a solid without passing through the liquid phase. Sublimation is commonly used to purify substances that can undergo this phase transition, such as iodine, dry ice, or camphor.
The heating provides enough energy for the molecules to overcome intermolecular forces and directly convert to vapour.
When the vapour is cooled, it condenses back into a solid, leaving impurities behind.
Thus, the correct purification method based on the described transformation is sublimation.
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
Inductance of a coil with \(10^4\) turns is \(10\,\text{mH}\) and it is connected to a DC source of \(10\,\text{V}\) with internal resistance \(10\,\Omega\). The energy density in the inductor when the current reaches \( \left(\frac{1}{e}\right) \) of its maximum value is \[ \alpha \pi \times \frac{1}{e^2}\ \text{J m}^{-3}. \] The value of \( \alpha \) is _________.
\[ (\mu_0 = 4\pi \times 10^{-7}\ \text{TmA}^{-1}) \]