To find the number of amino groups in the compound (\( x \)), we need to understand the change in molar mass due to acetylation. Acetylation involves replacing an amino hydrogen atom with an acetyl group (\( \text{CH}_3\text{CO} \)), which adds \( 42 \, \text{g mol}^{-1} \) to the molar mass per amino group modified.
1. Compute the difference in molar mass between the acetylated product and the original compound: \( 192 \, \text{g mol}^{-1} - 108 \, \text{g mol}^{-1} = 84 \, \text{g mol}^{-1} \).
2. Since each acetyl group increases the molar mass by \( 42 \, \text{g mol}^{-1} \), determine the number of acetyl groups added: \( \frac{84 \, \text{g mol}^{-1}}{42 \, \text{g mol}^{-1}} = 2 \) amino groups.
This computed value of 2 fits within the expected range of 2,2, confirming the solution is correct.
Each \(\text{NH}_2\) group increases molecular weight by 42 upon acetylation:
\[ 192 - 108 = 84 \] \[ \frac{84}{42} = 2 \]Thus, the compound \(x\) has:
\[ \text{2 amino groups.} \]What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)