To find the number of amino groups in the compound (\( x \)), we need to understand the change in molar mass due to acetylation. Acetylation involves replacing an amino hydrogen atom with an acetyl group (\( \text{CH}_3\text{CO} \)), which adds \( 42 \, \text{g mol}^{-1} \) to the molar mass per amino group modified.
1. Compute the difference in molar mass between the acetylated product and the original compound: \( 192 \, \text{g mol}^{-1} - 108 \, \text{g mol}^{-1} = 84 \, \text{g mol}^{-1} \).
2. Since each acetyl group increases the molar mass by \( 42 \, \text{g mol}^{-1} \), determine the number of acetyl groups added: \( \frac{84 \, \text{g mol}^{-1}}{42 \, \text{g mol}^{-1}} = 2 \) amino groups.
This computed value of 2 fits within the expected range of 2,2, confirming the solution is correct.
Each \(\text{NH}_2\) group increases molecular weight by 42 upon acetylation:
\[ 192 - 108 = 84 \] \[ \frac{84}{42} = 2 \]Thus, the compound \(x\) has:
\[ \text{2 amino groups.} \]A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.