




To solve this question, we need to understand the formation of azo-dyes, which generally involves a diazonium salt and a coupling component. Here, sulfanilic acid undergoes a diazotization reaction followed by coupling with a nitrogen-rich compound to form an azo dye.
The correct option involves the reaction forming an azo group (-N=N-) linked between two aromatic rings. This is typically represented by \(Ar-N=N-Ar'\), where Ar and Ar' are aromatic groups.
Given the options, the correct azo-dye formed is represented in the following image:
Therefore, the correct answer is the final option illustrated above.
The reaction involves the diazotization of sulphanilic acid, which forms a diazonium salt. This diazonium salt then couples with the compound \( C_6H_5NH_2 \), leading to the formation of the azo-dye product \( Y \).
The structure of \( Y \) matches option (4) in which the diazonium ion is coupled with the benzene ring of \( C_6H_5NH_2 \), forming the characteristic azo linkage (\(-N=N-\)) between the two aromatic rings.
Thus, the correct answer is: Option (4)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)