




To solve this question, we need to understand the formation of azo-dyes, which generally involves a diazonium salt and a coupling component. Here, sulfanilic acid undergoes a diazotization reaction followed by coupling with a nitrogen-rich compound to form an azo dye.
The correct option involves the reaction forming an azo group (-N=N-) linked between two aromatic rings. This is typically represented by \(Ar-N=N-Ar'\), where Ar and Ar' are aromatic groups.
Given the options, the correct azo-dye formed is represented in the following image:
Therefore, the correct answer is the final option illustrated above.
The reaction involves the diazotization of sulphanilic acid, which forms a diazonium salt. This diazonium salt then couples with the compound \( C_6H_5NH_2 \), leading to the formation of the azo-dye product \( Y \).
The structure of \( Y \) matches option (4) in which the diazonium ion is coupled with the benzene ring of \( C_6H_5NH_2 \), forming the characteristic azo linkage (\(-N=N-\)) between the two aromatic rings.
Thus, the correct answer is: Option (4)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,