Question:
The product of the pressure P and volume V of an ideal gas in a container is related to the translational part of the internal energy, E as
The product of the pressure P and volume V of an ideal gas in a container is related to the translational part of the internal energy, E as
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For monatomic ideal gas, internal energy = translational KE = \(\frac{3}{2}PV\).
Updated On: Apr 24, 2026
- \(E\)
- \(\sqrt{E}\)
- \(\frac{2E}{3}\)
- \(\frac{E}{3}\)
- \(2\sqrt{E}\)
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
For an ideal gas, translational kinetic energy \(E = \frac{3}{2}nRT\) and \(PV = nRT\).
Step 2: Detailed Explanation:
\(PV = nRT\)
\(E = \frac{3}{2}nRT = \frac{3}{2}PV\)
Therefore, \(PV = \frac{2}{3}E\)
Step 3: Final Answer:
\(PV = \frac{2E}{3}\).
For an ideal gas, translational kinetic energy \(E = \frac{3}{2}nRT\) and \(PV = nRT\).
Step 2: Detailed Explanation:
\(PV = nRT\)
\(E = \frac{3}{2}nRT = \frac{3}{2}PV\)
Therefore, \(PV = \frac{2}{3}E\)
Step 3: Final Answer:
\(PV = \frac{2E}{3}\).
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