The power \( P \) of a lens is related to its focal length \( f \) by the formula: \[ P = \frac{1}{f} \] where \( P \) is the power in diopters (D) and \( f \) is the focal length in meters. Given that the power of the corrective lens is \( P = -4.0 \, \text{D} \), we can find the focal length using the formula: \[ f = \frac{1}{P} \] Substituting \( P = -4.0 \, \text{D} \): \[ f = \frac{1}{-4.0} = -0.25 \, \text{m} = -25 \, \text{cm} \]
The correct option is (B) : concave lens of focal length -25 cm
The power of a lens (P) is related to its focal length (f) in meters by the formula:
\( P = \frac{100}{f(\text{in cm})} \Rightarrow f = \frac{100}{P} \)
Given: P = -4.0 D
\( f = \frac{100}{-4} = -25 \, \text{cm} \)
➤ A negative power indicates a concave lens.
✅ Correct answer: concave lens of focal length -25 cm
❌ Other options are incorrect because:
– Convex lenses have positive power.
– Focal length must match the power correctly.
Kepler's second law (law of areas) of planetary motion leads to law of conservation of
Kepler's second law (law of areas) of planetary motion leads to law of conservation of