Question:
The potential at a point at a distance \( r \) from the centre of an electric dipole is proportional to
The potential at a point at a distance \( r \) from the centre of an electric dipole is proportional to
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Remember: Dipole potential $\longrightarrow$ \(1/r^2\), Dipole field $\longrightarrow$ \(1/r^3\).
Updated On: Apr 22, 2026
- \( \frac{1}{r} \)
- \( \frac{1}{r^2} \)
- \( \frac{1}{r^3} \)
- \( r^2 \)
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The Correct Option is B
Solution and Explanation
Concept:
Electric potential due to a dipole:
\[
V = \frac{1}{4\pi \epsilon_0} \cdot \frac{p \cos\theta}{r^2}
\]
Step 1: Observe dependence on distance.
\[ V \propto \frac{1}{r^2} \]
Step 2: Conclusion.
Thus, potential varies inversely with square of distance.
Step 1: Observe dependence on distance.
\[ V \propto \frac{1}{r^2} \]
Step 2: Conclusion.
Thus, potential varies inversely with square of distance.
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