Question:

The phase velocity of a wave described by the equation $\psi = \psi_0 \sin (kx + \omega t + \frac{\pi}{2})$ is

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Phase velocity is always $\omega/k$, independent of phase constant.
Updated On: May 1, 2026
  • $\frac{x}{t}$
  • $\frac{\psi_0}{\omega}$
  • $\frac{\omega}{k}$
  • $\frac{\pi}{2k}$
  • $\psi_0$
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The Correct Option is C

Solution and Explanation


Concept:
Phase velocity: \[ v = \frac{\omega}{k} \]

Step 1:
Identify wave form.
Given: \[ \psi = \psi_0 \sin(kx + \omega t + \phi) \]

Step 2:
Compare with standard form.
Phase velocity depends only on $\omega$ and $k$. \[ v = \frac{\omega}{k} \]
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