Question:

The percentage error in the calculated volume of a sphere, if there is \(2%\) error in its diameter measurement, is _____.

Updated On: Apr 12, 2026
  • \(1\)
  • \(2\)
  • \(6\)
  • \(8\)
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The Correct Option is C

Solution and Explanation

Concept: Volume of a sphere: \[ V=\frac{4}{3}\pi r^3 \] Since diameter \(d=2r\), \[ V\propto d^3 \] For small errors: \[ \frac{\Delta V}{V}=3\frac{\Delta d}{d} \] Step 1: {Substitute the percentage error.} Given error in diameter: \[ \frac{\Delta d}{d}=2% \] Thus \[ \frac{\Delta V}{V}=3\times2% \] \[ =6% \] Step 2: {Interpret the result.} Thus the percentage error in the calculated volume is \[ 6% \]
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