Question:
The percentage by volume of C3H8 in a mixture of C3H8, CH4 and CO is 36.5. Calculate the volume of CO2 produced when 100 ml of the mixture is burnt in excess of O2.
The percentage by volume of C3H8 in a mixture of C3H8, CH4 and CO is 36.5. Calculate the volume of CO2 produced when 100 ml of the mixture is burnt in excess of O2.
Updated On: Aug 1, 2023
- (A) 175 ml
- (B) 173 ml
- (C) 150 ml
- (D) 123 ml
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The Correct Option is B
Solution and Explanation
Explanation:
Let the volumes of C3H8, CH4 and CO in the mixture be a, b and c m, respectively.Then, a + b + c = 100 ……. (i)Also, a = 36.5 …… (ii)Combustion reactions are as follow:C3H8 + 5O2 → 3CO2 + 4H2OCH4 + 2O2 → CO2 + 2H2OCO + ½O2 → CO2Therefore, volume of CO2 formed as a combustion of the mixture = 3a + b + c 3 X 36.5 + (b + c) = 3 X 36.5 + (100 - 36.5) = 173 ml
Let the volumes of C3H8, CH4 and CO in the mixture be a, b and c m, respectively.Then, a + b + c = 100 ……. (i)Also, a = 36.5 …… (ii)Combustion reactions are as follow:C3H8 + 5O2 → 3CO2 + 4H2OCH4 + 2O2 → CO2 + 2H2OCO + ½O2 → CO2Therefore, volume of CO2 formed as a combustion of the mixture = 3a + b + c 3 X 36.5 + (b + c) = 3 X 36.5 + (100 - 36.5) = 173 ml
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