Question:
The peak value of an alternating emf E given by $E=E₀ \cosω t$ is 10 V and its frequency is 50 Hz. At a time $t=\frac1600s$, the instantaneous value of the emf is
The peak value of an alternating emf E given by $E=E₀ \cosω t$ is 10 V and its frequency is 50 Hz. At a time $t=\frac1600s$, the instantaneous value of the emf is
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The peak value of an alternating emf E given by $E=E0 \cosω t$ is 10 V and its frequency is 50 Hz. At a time $t=1/600s$, the instantaneous value of the emf is
Updated On: Apr 15, 2026
- 10 V
- $5\sqrt{3}V$
- 5 V
- 1 V
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The Correct Option is B
Solution and Explanation
Step 1: Formula
$E = E_{0} \cos(2\pi f t)$.
Step 2: Substitution
$E = 10 \cos(2\pi \times 50 \times \frac{1}{600}) = 10 \cos(\frac{\pi}{6})$.
Step 3: Calculation
$E = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3} \text{ V}$.
Final Answer: (B)
$E = E_{0} \cos(2\pi f t)$.
Step 2: Substitution
$E = 10 \cos(2\pi \times 50 \times \frac{1}{600}) = 10 \cos(\frac{\pi}{6})$.
Step 3: Calculation
$E = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3} \text{ V}$.
Final Answer: (B)
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