Question:
The particle which is expected to be emitted along with \( Y \) in the following nuclear reaction is
\[
{ }^{198}_{80}X \rightarrow { }^{197}_{79}Y + ?
\]
The particle which is expected to be emitted along with \( Y \) in the following nuclear reaction is
\[
{ }^{198}_{80}X \rightarrow { }^{197}_{79}Y + ?
\]
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In nuclear reactions, when the atomic number decreases by 1, the particle emitted is a proton.
Updated On: Apr 7, 2026
- \( \alpha \)-particle
- \( \beta^+ \)-particle
- \( \beta^- \)-particle
- proton
- neutron
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The Correct Option is D
Solution and Explanation
In the given nuclear reaction: \[ ^{198}_{80}X \rightarrow ^{197}_{79}Y + ? \] The atomic number decreases by 1, implying the emission of a proton, as a proton carries a positive charge and reduces the atomic number by 1.
Hence, the correct answer is (D).
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