Step 1: Understand isomerism.
Isomers are compounds having the same molecular formula but different structures.
That means:
\[
\text{Same molecular formula}
\]
but:
\[
\text{Different arrangement of atoms}.
\]
Step 2: Find the molecular formula of the first compound.
The first compound is:
\[
\ce{CH3OCH2CH2CH3}
\]
Counting atoms:
\[
C=4,\quad H=10,\quad O=1
\]
So its molecular formula is:
\[
\ce{C4H10O}
\]
Step 3: Find the molecular formula of the second compound.
The second compound is:
\[
\ce{CH3CH2OCH2CH3}
\]
Counting atoms:
\[
C=4,\quad H=10,\quad O=1
\]
So its molecular formula is:
\[
\ce{C4H10O}
\]
Step 4: Compare the structures.
Both compounds have the same molecular formula:
\[
\ce{C4H10O}
\]
But the alkyl groups on the two sides of oxygen are arranged differently.
Therefore, they are isomers.
Step 5: Final conclusion.
Hence, the correct pair of isomers is:
\[
\ce{CH3OCH2CH2CH3}
\]
and:
\[
\ce{CH3CH2OCH2CH3}
\]