Question:
The oxidation number of sulphur in $\text{H}_2\text{SO}_4$ is}
The oxidation number of sulphur in $\text{H}_2\text{SO}_4$ is}
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Remember to use the rules for common elements and balance them with the overall charge of the molecule or ion.
Updated On: May 31, 2026
- +6
- +4
- -2
- 0
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The Correct Option is A
Solution and Explanation
Step 1: Concept
The oxidation number of an atom in a molecule or ion represents the charge it would have if the compound were composed of ions. It is determined by assigning charges to atoms based on certain rules, such as the electronegativity differences between atoms and the overall charge of the molecule.
Step 2: Meaning
In $\text{H}_2\text{SO}_4$, we need to find the oxidation number of sulfur (S). The sum of the oxidation numbers in a neutral compound is zero. Hydrogen typically has an oxidation number of +1, while oxygen usually has -2.
Step 3: Analysis
Let's denote the oxidation number of sulfur as \(x\). The equation for the sum of the oxidation numbers in \(\text{H}_2\text{SO}_4\) is: \[2(+1) + x + 4(-2) = 0\] Simplifying this, we get: \[2 - 8 + x = 0\] \[x - 6 = 0\] \[x = +6\] Thus, the oxidation number of sulfur in \(\text{H}_2\text{SO}_4\) is \(+6\).
Step 4: Conclusion
The correct assignment of oxidation numbers confirms that the answer is indeed +6. Final Answer: (A)
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