Question:
The output characteristics of a transistor is shown in the figure.
When VCE is 10 V and IC = 4.0 mA, then value of \(\beta_{ac}\) is __________.
The output characteristics of a transistor is shown in the figure.
When VCE is 10 V and IC = 4.0 mA, then value of \(\beta_{ac}\) is __________.
When VCE is 10 V and IC = 4.0 mA, then value of \(\beta_{ac}\) is __________.
Show Hint
\(\beta_{ac}=\left(\frac{\Delta I_C}{\Delta I_B}\right)_{V_{CE}}\); read the collector currents of neighbouring base-current curves at \(V_{CE}=10\) V around \(I_C=4\) mA.
Updated On: Nov 5, 2026
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Correct Answer: 150
Solution and Explanation
\(\beta_{ac}=\left(\frac{\Delta I_C}{\Delta I_B}\right)_{V_{CE}=\text{const}}\).
On the line \(V_{CE}=10\) V the output curves are flat. Reading the graph, the curve for \(I_B=20\ \mu\)A gives \(I_C\approx3\) mA and the curve for \(I_B=30\ \mu\)A gives \(I_C\approx4.5\) mA, so \(I_C=4.0\) mA lies in this interval.
\(\Delta I_C=4.5-3=1.5\) mA, \(\Delta I_B=30-20=10\ \mu\)A.
\(\beta_{ac}=\frac{1.5\times10^{-3}}{10\times10^{-6}}=150\).
Answer: 150
On the line \(V_{CE}=10\) V the output curves are flat. Reading the graph, the curve for \(I_B=20\ \mu\)A gives \(I_C\approx3\) mA and the curve for \(I_B=30\ \mu\)A gives \(I_C\approx4.5\) mA, so \(I_C=4.0\) mA lies in this interval.
\(\Delta I_C=4.5-3=1.5\) mA, \(\Delta I_B=30-20=10\ \mu\)A.
\(\beta_{ac}=\frac{1.5\times10^{-3}}{10\times10^{-6}}=150\).
Answer: 150
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