Question:
The osmotic pressure of a 5% (wt./vol.) solution of cane sugar at 150°C is:
The osmotic pressure of a 5% (wt./vol.) solution of cane sugar at 150°C is:
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The osmotic pressure can be calculated using the ideal gas law formula modified for solute concentration.
Updated On: Apr 22, 2026
- 3.078 atm
- 4.078 atm
- 5.078 atm
- 2.45 atm
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The Correct Option is C
Solution and Explanation
Step 1: Using the osmotic pressure formula.
Osmotic pressure (\( \Pi \)) is given by the formula: \[ \Pi = \frac{nRT}{V} \] where \( n \) is the number of moles of solute, \( R \) is the gas constant, \( T \) is the temperature in Kelvin, and \( V \) is the volume of the solution.
Step 2: Calculation at 150°C.
Converting the temperature to Kelvin: \[ T = 150 + 273 = 423 \, \text{K} \] We then calculate the osmotic pressure using the given concentration (5 percent solution), the gas constant, and other known values.
Step 3: Conclusion.
The correct osmotic pressure is \( 5.078 \, \text{atm} \).
Osmotic pressure (\( \Pi \)) is given by the formula: \[ \Pi = \frac{nRT}{V} \] where \( n \) is the number of moles of solute, \( R \) is the gas constant, \( T \) is the temperature in Kelvin, and \( V \) is the volume of the solution.
Step 2: Calculation at 150°C.
Converting the temperature to Kelvin: \[ T = 150 + 273 = 423 \, \text{K} \] We then calculate the osmotic pressure using the given concentration (5 percent solution), the gas constant, and other known values.
Step 3: Conclusion.
The correct osmotic pressure is \( 5.078 \, \text{atm} \).
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