The order of relative bond strength of oxygen molecule, superoxide ion and peroxide ion is
Show Hint
- $\mathrm{O}_2<\mathrm{O}_2^-<\mathrm{O}_2^{2-}$
- $\mathrm{O}_2>\mathrm{O}_2^->\mathrm{O}_2^{2-}$
- $\mathrm{O}_2<\mathrm{O}_2^->\mathrm{O}_2^{2-}$
- $\mathrm{O}_2>\mathrm{O}_2^-<\mathrm{O}_2^{2-}$
The Correct Option is B
Solution and Explanation
Bond order determines bond strength.
Step 2: Detailed Explanation:
Bond order: $\mathrm{O_2}$ (2), $\mathrm{O_2^-}$ (1.5), $\mathrm{O_2^{2-}}$ (1). Bond strength decreases with bond order.
Step 3: Final Answer:
$\mathrm{O}_2>\mathrm{O}_2^->\mathrm{O}_2^{2-}$.
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